Physics, asked by kpansh54, 4 months ago

29) Three resistors 492, 812 and 1032 are combined in parallel.
What is the total resistance of the combination?

Answers

Answered by prabhjitsinghgrewal

0

Explanation:

R1=492ohm

R2=812ohm

R3=1032ohm

When resistors are combined in parallel,their equivalent resistance i.e. total resistance(R)=

1/R=1/492 + 1/812 + 1/1032

=>1/R=36359/8589336

=>R=8589336/36359=236.24ohm(approx.) ans.

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