29. Two cells of emf E, and E, (E, > E, are
connected individually to a potentiometer and their
corresponding balancing length are 625 cm and
500 cm, then the ratio E1/E2
Answers
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0
Answer:
e
2
e
1
=
3
2
Explanation:
The net emf of the two cells in the two cases
e
2
+
e
1
and
e
2
−
e
1
, respectively. Since the emf is proportional to the balance length
e
2
+
e
1
e
2
−
e
1
=
625
125
=
5
1
Thus
e
2
e
1
=
(
e
2
+
e
1
)
+
(
e
2
−
e
1
)
(
e
2
+
e
1
)
−
(
e
2
−
e
1
)
=
5
+
1
5
−
1
=
3
2
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