Math, asked by dhanabala007, 6 hours ago

29. Two crossroads each 2 m wide intersect each other at right angles through the centre of rectangular area of dimension 75 m x 50 m. These crossroads run parallel to sides of the rectangle. Find the area of crossroads.​

Answers

Answered by Anonymous
23

Step-by-step explanation:

area of the road 1 = 75*2

= 150m^2

area of second road = 50*2

= 100m^2

add the areas of roads

= 100+150

= 250m^2

subtract the area of a square of 2m side made at center of rectangular shape

2*2

= 250-4

= 246m^2 (ans.)

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Answered by Anonymous
19

Area of first crossroad which is rectangular

 \tt =  length \times breadth

Hence area = 72m × 2m = 144m²

Area of 2nd crossroad which is rectangular

= 48m × 2m = 96m²

Area of middle part which is square = 2m × 2m

= 4m^2

Area of crossroad = (144+96)m² - 4m²

= 240m²- 4m² = 236m²

I Hope it will help you

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