Question

.29 Two tall buildings are 30 m apart. The speed with which
a ball must be thrown horizontally from a window 150
m above the ground in one building so that it enters a
window 27.5 m from the ground in the other building is
a. 2 ms-1
b. 6 ms -1
c. 4 ms.
d. 8 ms-​

Answer 1

Answer:option b

i.e. 6 m/s

Explanation:

Refer pic

Plese mark me as brainest

I need it to upgrade my rank..

Answer 2

ANSWER:

Option b. 6m/sec

EXPLANATION:

The distance between the building is taken as 30 meters, now the distance between the floor 150 m to window 27.5 m, is taken as  

Distance, d = 150 - 27.5 = 122.5 m

Therefore, to find the time taken to cover this distance of 122.5 m is

$S=u t+\frac{1}{2} a t^{2}$

Now in the above equation, the value of initial velocity is taken as zero we get the time, t =

$122.5=\frac{1}{2}(9.8) t^{2}$

The acceleration in the above formula is taken as $a=9.8 m / s^{2}$

Therefore, the time, t = 5sec

Now, the velocity to reach other building is  

S = V x T, V = 30/5 = 6 m/sec

Therefore, the velocity of the ball is 6 m/sec