CBSE BOARD XII, asked by shabnams1199, 6 months ago

290. A body of mass 5 kg is moving with a velocity
of 10 m/s along a surface. The resistance by the
surface is 20 N. The body will stop after.
A.10 m
D. 12
B. 12.5 m
C. 15.5 m​

Answers

Answered by userg4470
9

Answer:

M=5kg

a=

t

v−u

1

V−10

f=20N

f=m×a

20N=5kg×(V−10)

4=(v−10)

v=14

Explanation:

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