290 mL of a gas at 17 °C is cooled to –13 °C at constant pressure. The new volume of the gas will be
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Answer:
V1/T1 = V2/T2
290/(273+17)=V2/(273-13)
290/290=V2/250
V2= 250 ml
The new Volume will be 250ml
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Explanation:
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V1/T1 = V2/T2
290/(273+17)=V2/(273-13)
290/290=V2/250
V2= 250 ml
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