Question

290 ml of a gas at 17 °c is cooled to –13 °c at constant pressure. The new volume of the gas will be

Answer 1

V1/T1 = V2/T2
290/(273+17)=V2/(273-13)
290/290=V2/250
V2= 250 ml



The new Volume will be 250ml

Answer 2

Answer:

V1/T1=V2/T2

290÷273+17=V2÷273-13

1=V2÷260

then V2 is equal to 260ml