290 ml of a gas at 17 °c is cooled to –13 °c at constant pressure. The new volume of the gas will be
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V1/T1 = V2/T2
290/(273+17)=V2/(273-13)
290/290=V2/250
V2= 250 ml
The new Volume will be 250ml
290/(273+17)=V2/(273-13)
290/290=V2/250
V2= 250 ml
The new Volume will be 250ml
Answered by
1
Answer:
V1/T1=V2/T2
290÷273+17=V2÷273-13
1=V2÷260
then V2 is equal to 260ml
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