294 joules of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from 30°C to 35 C. The amount of heat required
to rise the temperature of the same gas through the same range of temperature at constant volume (R 8.3 Joules/mole/K) is
(A) 126 J
(B) 211
(C)294 J
(D) 378 J
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Answer:
Explanation:
Heat = moles(no.) ×C
P
×△T
⇒310=2×C
P
×10[35−25=10]
⇒C
P
=15.5J/molK
∴C
P
−C
V
=R
⇒C
V
=C
P
−R=15.5−8.314
⇒C
V
=7.186J/molK
Q=nC
V
△T
=2×7.186×10
=143.72J≈144J
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