294 notebooks,252 pens and 210 pencils are distributed equally among some students with none left over. what is the biggest possible no. of students...
Answers
Answered by
40
294 = 2 × 3 × 7^2
252 = 2^2 × 3^2 × 7
210 = 2 × 3 × 5 × 7
HCF = 2 × 3 × 7
HCF = 42 students
252 = 2^2 × 3^2 × 7
210 = 2 × 3 × 5 × 7
HCF = 2 × 3 × 7
HCF = 42 students
Answered by
33
Solution :-
To find the biggest possible number of students, so that among them 294, notebooks, 252, pens and 210 pencils can be distributed, we have to find the H.C.F. of 294, 252 and 210
__________________
2 | 294, 252, 210
|_________________
3 | 147, 126, 105
|_________________
7 | 49, 42, 35
|_________________
| 7, 6, 5
|
H.C.F. of 294, 252 and 210 = 2*3*7 = 42
So, the biggest possible number of students is 42.
Answer.
To find the biggest possible number of students, so that among them 294, notebooks, 252, pens and 210 pencils can be distributed, we have to find the H.C.F. of 294, 252 and 210
__________________
2 | 294, 252, 210
|_________________
3 | 147, 126, 105
|_________________
7 | 49, 42, 35
|_________________
| 7, 6, 5
|
H.C.F. of 294, 252 and 210 = 2*3*7 = 42
So, the biggest possible number of students is 42.
Answer.
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