29x+32y=26 and 32x+29y=35 by substitution method or elimination method solve this
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Hey!!
By Elimination method
29x + 32y = 26----------(1) × 32
32x + 29y = 35-----------(2) × 29
eq'n (1) 928x + 1024y = 832
eq'n (2) 928x + 841y = 1015
----------------------------------
=> 183y = - 183
=> y = - 1
From eq'n (2)
=> 32x + 29 (-1) = 35
=> 32x - 29 = 35
=> 32x = 35 + 29
=> x = 64 / 32
=> x = 2
Therefore the value of x = 2 and y = - 1
_________________________
Hope it will helps you ✌ ✌
By Elimination method
29x + 32y = 26----------(1) × 32
32x + 29y = 35-----------(2) × 29
eq'n (1) 928x + 1024y = 832
eq'n (2) 928x + 841y = 1015
----------------------------------
=> 183y = - 183
=> y = - 1
From eq'n (2)
=> 32x + 29 (-1) = 35
=> 32x - 29 = 35
=> 32x = 35 + 29
=> x = 64 / 32
=> x = 2
Therefore the value of x = 2 and y = - 1
_________________________
Hope it will helps you ✌ ✌
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