Question

(2a+1)^3+(a-1)^3.
Pls do help me

Answer 1

Step-by-step explanation:(2a+1)^3=(a+b)^3=a^3+3a^2b+3ab^2+b^3

(a-1)^3=(a-b)^3=a^3-3a^2b+3ab^2-b^3

{(2a)^3+3×(2a)^2×1+3×2a×(1)^2+(1)^3}+{(a)^3-3×(a)^2×1+3×a×(1)^2-(1)^3}

=8a^3+12a^2+6a+1+a^3-3a^2+3a-1

=8a^3+a^3+12a^2-3a^2+6a+3a

=9a^3+9a^2+9a

=9(a^3+a^2+a)

Answer 2

Step-by-step explanation:

${a}^{3} + {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2}$

(2a+1+a-3)(4a^2 +4a +1 - 2a^2 +2a - a + 1 +a^2-2a+1)

Now you can further solve it