Math, asked by vshernitha, 7 months ago

(2a+1/3a)^2 + 2a-1/3a)^2 evaluate

Answers

Answered by SoumiMaiti
0

Answer:

8a^2 + 2/9a^2

Step-by-step explanation:

(2a + 1/3a)^2 + (2a - 1/3a)^2

= (2a + 1/3a + 2a - 1/3a)^2 - 2 x (2a + 1/3a) x (2a - 1/3a)

= (4a)^2 - 2 x {(2a)^2 - (1/3a)^2}

= 16a^2 - 2 x (4a^2 - 1/9a^2)

= 16a^2 - 8a^2 + 2/9a^2

= 8a^2 + 2/9a^2

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