Question

(2a-1/a)² please tell the ans​

Answer 1

...........♣️ QUESTION ♣️...........

${(2a - \frac{1}{a}) }^{2}$

.............♣️ ANSWER ♣️.............

$by \: \: \: using \: \: \: the \: \: \: \: formula \: \: \: \\ {(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy \\ \\ here \: \: \: x = 2a \\ \: \: \: \: \: \: \: \: \: \: \: y = \frac{1}{a} \\ \\ {(2a - \frac{1}{a} )}^{2} = ({2a})^{2} + ( { \frac{1}{a} })^{2} - 2(2a \times \frac{1}{a} ) \\ \\ = 4 {a}^{2} + \frac{1}{ {a}^{2} } - 2 \times 2 \\ \\ = 4 {a}^{2} + \frac{1}{ {a}^{2} } - 4$

.........♣️ THIS IS THE ANSWER TO UR QUESTION ♣️......

Answer 2

Answer:

The answer is 4a² + 1/a² - 4

Step-by-step explanation:

Identity = (a - b)² = (a)² + (b)² - 2ab

(2a - 1/a)² = (2a)² + ( 1/a)² - 2 × 2a × 1/a

= 4a² + 1/a² - 4a/a

= 4a² + 1/a² - 4