Question

(2a+1)whole cube +(a-1)whole cube

Answer 1

The expression is $(2a+1)^3+(a-1)^3=9a^3+9a^2+9a$

Step-by-step explanation:

Given : Expression (2a+1)whole cube +(a-1)whole cube.

To find : Solve the expression ?

Solution :

Write the expression in algebraic form and solving it,

$(2a+1)^3+(a-1)^3$

Using cubic identity, $(a+b)^3=a^3+b^3+3a^2b+3ab^2$

$(2a+1)^3+(a-1)^3=(2a)^3+(1)^3+3(2a)^2(1)+3(2a)(1)^2+(a)^3+(-1)^3+3(a)^2(-1)+3(a)(-1)^2$

$(2a+1)^3+(a-1)^3=8a^3+1+12a^2+6a+a^3-1-3a^2+3a$

$(2a+1)^3+(a-1)^3=9a^3+9a^2+9a$

Therefore, the expression is $(2a+1)^3+(a-1)^3=9a^3+9a^2+9a$

#Learn more

A+b-3+(b-a+3)+(a-b+3)

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