Question

(2a-1)x-3y=5
3x+(b-2)y=3
(CBSE 2002)​

Answer 1

Given, pair of equations

(2a – 1)x – 3y = 5

and 3x + (b – 2)y = 3

On comparing the given equation with standard form i.e. a1 x + b1y + c1 = 0 and a2 x + b2y + c2 = 0, we get

a1 = (2a – 1), b1 = – 3 and c1 = – 5

and a2 = 3, b2 = b – 2 and c2 = 3

For infinitely many solutions,

Here,

On taking I and III terms, we get

⇒ 3(2a – 1) = 15

⇒ 6a – 3 = 15

⇒ 6a = 15 + 3

On taking II and III terms, we get

⇒ – 9 = 5(b – 2)

⇒ 5b – 10 = – 9

⇒ 5b = – 9 + 10

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