Question

(2a^2-3ab+7)+-a+3ab-a+b^3

Answer 1

Answer:

13

Step-by-step explanation:

We can solve it in two ways,

First, by taking the square of (a+b)

(a+b)^2=7^2

=>a^2+b^2+2ab=49

=>a^2+b^2+2x12=49

=>a^2+b^2=49–24=25

=>a^2+b^2-ab=25-ab

=>a^2+b^2-ab=25–12=13.

Secondly, we can separately find the values of ‘a’ and ‘b’ and calculate the given equation.

a+b=7……….(1)

ab=12………(2)

eliminating ‘a’, we get b=3,4

so we get a=4,3

Putting both the values of ‘a’ and ‘b’, we get the answer to be 13.