Question

2a^2+a-10/2a+5 dividing a polynomial by a monomial

Answer 1

2a^2+a-10/2a+5

(Remainder theorem)

2a+5=0

a= -5/2

We put this value in equation

-2×(5/2)^2+5/2-10

-2×25/4+5/2-10

-25/2-5/2-10

-25-5-20/2

-50/2

-25

So, -25 is the answer