2a+√2 a=6+3√2 find the answer
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Answer:
2a+√2 a=6+3√2
a(2+√2)=3(2+√2)
therefore, a=3
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[tex]2a + \sqrt{2} a = 6 + 3 \sqrt{2} \\ a(2 + \sqrt{2}) = 3(2 + \sqrt{2} )\\ \sqrt{2 } + \sqrt{2} = 2 - 2 \\ 2 \sqrt{2} = 0[tex]
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