Question

2a=(2/x--x)^2 find the value of a​

Answer 1

Answer:

2a=(2/x-x)

2a=[ (2/x)^2-2(x)(2/x)+(x)^2]

2a=(4/x^2-4+x^2)

2a=(4lx^2-4+x^2)

2a=(4-4x^2+x^4)/x^2

a=(4-4x^2+x^4)/2x^2

in second step we use formula of (a+b)^2