(2a+2b)2
![(2a + 2b) {?}^{2} (2a + 2b) {?}^{2}](https://tex.z-dn.net/?f=%282a+%2B+2b%29+%7B%3F%7D%5E%7B2%7D+)
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Hi Friend ✋✋✋
( 2a + 2b ) ²
We can do it by using Identity I
( a + b )² = a² + b² + 2ab
So,
( 2a + 2b ) ² = ( 2a )² + ( 2b )² + 2 ( 2a ) ( 2b )
( 2a + 2b ) ² = 4a² + 4b² + 8ab = 4 ( a² + b² + 2ab ) = 4 × ( a + b ) ²
Hope it helps
( 2a + 2b ) ²
We can do it by using Identity I
( a + b )² = a² + b² + 2ab
So,
( 2a + 2b ) ² = ( 2a )² + ( 2b )² + 2 ( 2a ) ( 2b )
( 2a + 2b ) ² = 4a² + 4b² + 8ab = 4 ( a² + b² + 2ab ) = 4 × ( a + b ) ²
Hope it helps
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