2A + 2B-2C + 2B
If 5 moles of A and 6 moles of B are made to react, the limiting reagent is reactant
(1) A
(2) B
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Explanation:
If you're given the moles present of each reactant, and asked to find the limiting reactant of a certain reaction, then the simplest way to find which is limiting is to divide each value by that substance's respective coefficient in the (balanced) chemical equation; whichever value is smallest is the limiting reactant
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