(2a)³-(3b)³ factorise
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Answer:
(2a - 3b) (4a^2 + 6ab + 9b^2 )
Step-by-step explanation:
we know -
a^3 – b^3 = (a – b) (a^2 + ab + b^2 )
now, (2a)³-(3b)³
= (2a - 3b) {(2a)^2 + (2a*3b) +(3b)^2}
= (2a - 3b) (4a^2 + 6ab + 9b^2 )
Answered by
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(a-b)(a square+ab+b square)
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