Math, asked by mantejhanda61, 1 year ago

(2a)³-(3b)³ factorise​

Answers

Answered by MITAN19
0

Answer:

(2a - 3b) (4a^2 + 6ab + 9b^2 )

Step-by-step explanation:

we know -

a^3 – b^3 = (a – b) (a^2 + ab + b^2 )

now, (2a)³-(3b)³

= (2a - 3b) {(2a)^2 + (2a*3b) +(3b)^2}

= (2a - 3b) (4a^2 + 6ab + 9b^2 )

Answered by sneha2154
0

(a-b)(a square+ab+b square)

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