(2a‐³ b²)³ chapter indices pls tell
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Answer:⇒(2a-³ b²) ³ =(2a⁻³)³ × (b²)³
= (2)³ × (a⁻³)³ × (b²)³ from the (yⁿ)ᵃ = y⁽ⁿ ˣ ᵃ⁾ = yⁿᵃ and a⁻ⁿ=1/aⁿ
= 2³ × a⁻⁹ ₓ b⁻⁶
= 8 × 1/a⁹ × 1/b⁶
= (8)/(a⁹ × b⁶)
= (8)/(a⁹b⁶)
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