Question

2a(3a³+6b) - 1/2b(4a²-2ab)
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Answer 1

Answer:

In triangles AOC and BOD, we have

AO = BO (O, the midpoint of AB);

∠AOC=∠BOD, (vertically opposite angles);

CO=OD, (O, the midpoint of CD)

So by SAS postulate we have

△AOC≅△BOD.

Hence, AC = BD, as they are corresponding parts of congruent triangles.

Step-by-step explanation:

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