Question

(2a+3b-12)^2+(a-2b-6)^2=0 then a=?,b=?​

Answer 1

( 2a + 3b - 12 )^2 + ( a - 2b - 6) ^2 = 0

4a^2 + 9b^2 - 144 + a^2 - 4b^2 - 36 = 0

4a^2 + a^2 + 9b^2 - 4b^2 - 144 -36

5a^2 + 5b^2 - 190 = 0

5a^2 + 5b^2 = 190

a^2 + 5b^2 = 190 / 5

a^2 + 5b^2 = 34

a^2 + b^2 = 3.8

a = 34 and b = 3.8

Answer 2

Step-by-step explanation:

I hope this will be understand you