Question

2a+3b=14and3a+2b=16
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Answer 1

Answer:

a=4 and b=2

Step-by-step explanation:

Let 2a+3b=14 be equation 1 and 3a +2b=16 be equation 2. now multiply equation 1 by 2 and equation 2 by 3.

now subtract the 2 new equations formed,i.e, 4a+6b=28 and 9a+6b=48.

we see that on subtraction the term containing b will be eliminated and we get 5a=20.

now we divide the above equation by 5 on bith sides, we get a=4.

Now put this value un any of the equations to find the value of b. If I put it in equation 1 we get, 2×4+3b=14,i.e., 8+3b=14

Adding -8 on both sides,

3b=6

Dividing both sides by 3,

b=2

Hope it helps...