2a+3b=15 and ab=10 find 2a×2a×2a + 3b×3b×3b
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Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝
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2a×2a ×2a+3b×3b×3b=(2a)^3+(3b)^3=
(2a+3b)^3-3(4a^2)(3b)-3(9b^2)(2a)=
15^3-3(3)2ab(2a+3b)
=15^3-18(10)(15)
=15(15^2-180)
=15(225-180)
=15×45
=675
(2a+3b)^3-3(4a^2)(3b)-3(9b^2)(2a)=
15^3-3(3)2ab(2a+3b)
=15^3-18(10)(15)
=15(15^2-180)
=15(225-180)
=15×45
=675
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