Math, asked by anchalshukla7212, 8 months ago

(2a^-3b^2)^3
How can we solve with laws of indices

Answers

Answered by tahabrigade
1

Step-by-step explanation:

Apply the formula of ( a -b )^3 .

Juss 2 - 3 steps answer.

U ll get it easily .. :)

Answered by AbhirupSarkar
2

(2a^-3 b^2)³

=> (b²/2a³)³ [Taking 2a^-3 to denominator

as it has - sign ]

=> b⁶/8a⁹. [By multiplying]

(Ans.)=>8a^-9 b⁶. [Taking 2a³ back to

numerator] {optional step}

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