(2a +3b)²- 4c² factorise
Answers
Answered by
3
Answer:
(
2
+
3
)
2
−
4
2
(
2
+
3
)
(
2
+
3
)
−
4
2(
2
+
3
)
(
2
+
3
)
−
4
2
2
(
2
+
3
)
+
3
(
2
+
3
)
−
4
22
(
2
+
3
)
+
3
(
2
+
3
)
−
4
2
4
2
+
6
+
3
(
2
+
3
)
−
4
2
44
2
+
6
+
3
(
2
+
3
)
−
4
2
4
2
+
6
+
6
+
9
2
−
4
2
Solution
4
2
+
1
2
+
9
2
−
4
2
Answered by
1
Answer:
We have,
a2−(2a+3b)2
=(a−(2a+3b))(a+(2a+3b))∴a2−b2=(a+b)(a−b)
=(a−2a−3b)(a+2a+3b)
=(−a−3b)(3a+3b)
=−3(a+3b)(a+b)
Step-by-step explanation:
please mark my answer in brainlist please
Similar questions