Question

(2a+3b+2c)^2 expand using suitable identity​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer :-

$\sf (2a + 3b + 2c)^{2}$

$\sf {(2a)}^{2} + {(3b)}^{2} + {(2c)}^{2} + 2(2a \times 3b) + 2(3b \times 2c) + 2(2c \times 2a)$

$\sf {(4a)}^{2} + {(9b)}^{2} + {(4c)}^{2} + 12ab + 12bc + 8ca$

Procedure :-

→ By using the 5th Algebraic identity we will solve this equation. The 5th says that (a+b+c)² = a²+b²+c²+2ab+2bc+2ca. then we will do the square of 2, 3 and 2 which are a, b and c.

→ And the we will multiply the numbers which are given in the brackets and then we will multiply it with 2 which is outside the bracket as shown above.

→ After equating the whole expression the final answer is 4a² + 9b² + 4c² + 12ab + 12 bc + 8ca.

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