Math, asked by nishu24164, 2 months ago

(2a) + (3b)3 + 3(2a)(3b)(2a + 3b)​

Answers

Answered by Mfislam
2

(2a+3b)^3

(2a)3 + (3b)3 + 3(2a)(3b)(2a + 3b)

[(a+b)3 = a^3+b^3+3ab(a+b)]

= (2a+3b)*3.

Answered by Mysteryboy01
0

 (2a) + (3b)3 + 3(2a)(3b)(2a + 3b)

 = (2a + 3b) ^{3}

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