2a+3b-3(a+3b)^2 factorise
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2(a+3b) – 3(a+3b) 2 Now by taking (a+3b) as a common factor for the above equation we get, 2(a+3b) – 3(a+3b)2 = (a+3b) (2 – 3(a+3b)) = (a+3b) (2- 3a -9b)Read more on Sarthaks.com - https://www.sarthaks.com/733888/factorise-2a-6b-3-a-3b-2
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