Question

(2a-3b)³ cubes in expanded form​

Answer 1

Given –

(2a-3b)³

We know the algebraic identity,

( x - y )³ = x³ - 3x²y + 3xy² - y³

Now ,

( 2a - 3b )³

➛ = (2a)³-3*(2a)²*3b+3*2a*(3b)²-(3b)³

➛ = 8a³ - 3*4a²*3b+6a*9b²-27b³

➛ = 8a³ - 36a²b + 54ab² - 27b³

Answer 2

Step-by-step explanation:

Given –

(2a-3b)³

We know the algebraic identity,

( x - y )³ = x³ - 3x²y + 3xy² - y³

Now ,

( 2a - 3b )³

➛ = (2a)³-3*(2a)²*3b+3*2a*(3b)²-(3b)³

➛ = 8a³ - 3*4a²*3b+6a*9b²-27b³

➛ = 8a³ - 36a²b + 54ab² - 27b³