Math, asked by ashmitas949, 8 months ago

2a-3b-[3a-2b-{a-c+(a-2b)}]​

Answers

Answered by Anonymous
17

ANSWER

\sf\therefore 2a-3b-[3a-2b-{a-c+(a-2b)}]

\sf\implies 2a-3b-[3a-2b-a+c-a+2b]

\sf\implies 2a-3b-3a+2b+a-c+a-2b

\sf\implies 2a-3a+a+a-3b+2b-2b-c

\sf\implies  -a+a+a-3b-c

\sf\implies a-3b-c

\large{\boxed{\bf{ \star\:\: a-3b-c \:\: \star}}}

___________________

Answered by Rudranil420
60

Answer:

➡2a−3b−[3a−2b−a−c+(a−2b)]

=> 2a−3b−[3a−2b−a+c−a+2b]

=> 2a−3b−3a+2b+a−c+a−2b

=> 2a−3a+a+a−3b+2b−2b−c

=> −a+a+a−3b−c

=> a−3b−c ✔

\bold{\huge{\fbox{\color{blue} {a-3b-c}}}}

Step-by-step explanation:

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