Question

(2a+3b+4c)^2-(2a-3b+4c)^2​

Answer 1

Step-by-step explanation:

${4a}^{2} +{9b}^{2} + {16c}^{2} \\ - 4 {a}^{2} + 9 {b}^{2} - 16 {c}^{2} \\ \\ 18 {b}^{2} \\ \\ 2 \times 3 \times 3 \times {b}^{2} \\ 2(3 {b}^{2})$