Question

(2a-3b+4c)^2+(2a+3b-4c)^2(29-36+40)(2a+3b-4c)​

Answer 1

Correct option is A)

We know,

(x+y+z)2=x2+y2+z2+2xy+2yz+2zx        [Identity]

Here, 

x=2a

y=3b

z=4c

Putting Values in Identity, We get :

⇒ (2a+3b+4c)2=(2a)2+(3b)2+(4c)2+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

                                  =4a2+9b2+16c2+12ab+24bc+16ca