Question

(2a-3b+4c)^2+(2a+3b-4c)^2(29-36+40)(2a+3b-4c)​

Answer 1

Answer:

Step by Step Solution

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STEP

1

:

Equation at the end of step 1

((2a-3b+4c)2)+(33•(2a+3b-4c)2•(2a+3b-4c))

STEP

2

:

Evaluate an expression:

2.1 Multiply (2a+3b-4c)2 by (2a+3b-4c)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (2a+3b-4c) and the exponents are :

2

and 1 , as (2a+3b-4c) is the same number as (2a+3b-4c)1

The product is therefore, (2a+3b-4c)(2+1) = (2a+3b-4c)3

Equation at the end of step

2

:

((2a - 3b + 4c)2) + 33 • (2a + 3b - 4c)3

STEP

3

:

3.1 Evaluate : (2a-3b+4c)2 = 4a2-12ab+16ac+9b2-24bc+16c2

3.2 Evaluate : (2a+3b-4c)3 = 8a3+36a2b-48a2c+54ab2-144abc+96ac2+27b3-108b2c+144bc2-64c3

Final result :

264a3+1188a2b-1584a2c+4a2+1782ab2-4752abc-12ab+3168ac2+16ac+891b3-3564b2c+9b2+4752bc2-24bc-2112c3+16c2