Question

(2a+3b+4c)2 alegbra​

Answer 1

Answer:

$we \: know \: that \: ( {a + b + c})^{2} = {a}^{2} + { b}^{2} + {c}^{2} + 2ab + 2bc + 2ca \\ ({2a + 3b + 4c})^{2} = ({2a})^{2} + ({3b})^{2} + ({4c})^{2} \: + 2 \times 2a \times 3b + 2 \times 3b \times 4c + 2 \times 4c \times 2a \\ 4 {a}^{2} \: + 9 {b} ^{2} \: + 16 {c}^{2} \: + 12ab + 24bc + 16ac$