Question

(2a-3b+4c)^2 answer please
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Answer 1

Answer:

We know,

(x+y+z)

2

=x

2

+y

2

+z

2

+2xy+2yz+2zx [Identity]

Here,

x=2a

y=3b

z=4c

Putting Values in Identity, We get :

⇒ (2a+3b+4c)

2

=(2a)

2

+(3b)

2

+(4c)

2

+2(2a)(3b)+2(3b)(4c)+2(4c)(2a)

=4a

2

+9b

2

+16c

2

+12ab+24bc+16ca