(2a+3b+4c)² can you solve this
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Answer:
(2a+3b+4c)×(2a+3b+4c)
=2a(2a+3b+4c)+3b(2a+3b+4c)+4c(2a+3b+4c)
=4a2+6ab+8ac+6ab+9b2+12bc+8ac+12bc+16c2
=4a2+9b2+16c2+6ab+6ab+8ac+8ac+12bc+12bc
=4a2+9b2+16c2+12ab+16ac+24bc
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