Question

(2a+3b-4c)2
find the square of the following?? ​

Answer 1

${2a + 3b - 4c}^{2}$

$= {2a}^{2} + {3b}^{2} + {4x}^{2} + 2.2a.3b + 2.2a.4x + 2.3b.4x$

$= {4a}^{2} + {9b}^{2} + {16x}^{2} + 12ab + 16ax + 24bx$

Please mark it BRAINLIEST ✏️✏️✏️✏️

Answer 2

Step-by-step explanation:

To find the square of (2a+3b-4c)2 we will use the VII that is

(x+y+z)2=x^2+y^2+z^2+2xy+2yz

+2zx

Now,

(2a+3b-4c)2

=(2a)^2+(3b)^2+(-4c)^2+2×2a×3b

+2×3b×(-4c)+2 ×(-4c)×2a

=4a^2+9b^2+16^2+12ab-24bc-16ac