Question

2a+3b=6 and 3a+5b=15​

Answer 1

Answer:

Let us consider the equation 2a+3b=6 and write it as

b= 36−2a

.........(1)

Substitute the value of b in Equation 3a+5b=15. We get

3a+5( 36−2a )=15

⇒9a+5(6−2a)=45

⇒9a+30−10a=45

⇒−a=45−30

⇒a=−15

Therefore, a=−15

Substituting this value of a in Equation (1), we get

b= 36−(−30)

b= 3

36 =12

Hence, the solution is a=−15,b=12.