Question

(2a+(-3b))(-6a+(-8)) full solution send kro plz chapter algebraic ​

Answer 1

Step-by-step explanation:

The given series are (2a−b),(4a−3b),(6a−5b),...n terms

∴a=(2a−b)

and d=((4a−3b)−(2a−b))=2a−2b=2(a−b)

∴S

n

=2a+(n−1)d

⟹S

n

=2(2a−b)+[(n−1)×2(a−b)]

⟹S

n

=(4a−2b)+[(2a−2b)×(n−1)]

=4a−2b−2a+2b+2an−2bn

=2a+2an−2bn

S

n

=2[a(2n+1)−bn]

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Answer 2

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Step-by-step explanation:

(2a-3b)(-6a-8)

2a(-6a-8)-3b(-6a-8)

= -12a²-16a+18ab+24b