2a=3b=6c,then c=ab/a+b
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LET 2a=3b=6c= x
therefore
2a= x⇒a=x/2
3b=x⇒b=x/3
6c=x⇒c=x/6
rhs=ab/a+b
= (x/2*x/3)/(x/2+x/3)
=(x²/6)/(3x+2x)/6
=x²/5x
=x/5
≠c
≠lhs
plz ,check ur problem
therefore
2a= x⇒a=x/2
3b=x⇒b=x/3
6c=x⇒c=x/6
rhs=ab/a+b
= (x/2*x/3)/(x/2+x/3)
=(x²/6)/(3x+2x)/6
=x²/5x
=x/5
≠c
≠lhs
plz ,check ur problem
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