(2a+3b+7c) (3a+6b+c) -a (b+c)
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Starting with the second given equation;
3a + 5b + 7c = 30
(2a + 3b + 4c) + (a + 2b + 3c) = 30
35 + (a + 2b + 3c) = 30
a + 2b + 3c = -5______(1)
Now, using the first equation
2a + 3b + 4c = 35
( a + 2b + 3c) + (a + b + c)=35
-5 +(a + b + c)=35 [ using__(1)]
a + b +c=40
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