(2a + 3b)(a - b) = 2a² - 3b²
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(2a+3b)(a-b)=2a²–3b²
2a²+ab–3b²=2a²–3b²
which is only possible when, ab=0
i.e., a=0 or b=0
Now, we can say that,
LHS=2a²–3b²=RHS
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