Question

(2a +3b +c)^2 expand

Answer 1

Answer:

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(2a +3b +c)^2

(2a +3b +c)^2

= (2a)^2 + (3b)^2 +(c)^2 +2 (2a+3b) +2 (3b+c)+2 (2a+c)

(2a +3b +c)^2

= (2a)^2 + (3b)^2 +(c)^2 +2 (2a+3b) +2 (3b+c)+2 (2a+c)

=4(a^2 )+9(b^2) +(c^2)+ 4a+6b +6b +2c +4a +2c

(2a +3b +c)^2

= (2a)^2 + (3b)^2 +(c)^2 +2 (2a+3b) +2 (3b+c)+2 (2a+c)

=4(a^2 )+9(b^2) +(c^2)+ 4a+6b +6b +2c +4a +2c

=4(a^2 )+9(b^2) +(c^2)+ 8a + 12b + 4c

Answer 2

Step-by-step explanation:

(2a+3b+c)'2=

4a'2+9b'2+c'2+2(2a*3b)+2(3b*c)+2(2a*c)

4a'2+9b'2+c'2+4a*6b+6b*2c+4a*2c

4a'2+9b'2+c'2+24ab+12bc+8ac