Question

(2a – 3b + c )^2
please solve this for me ​

Answer 1

Step-by-step explanation:

We know that,

(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz

Therefore,

(2a–3b+c)^2=(2a)^2+(–3b)^2+(c)^2+2(2a×–3 b)+2(–3b×c)+2(2a×c)

4a^2+9b^2+c^2+2(-6ab)+2(-3bc)+2(2ac)

4a^2+9b^2+c^2-12ab-6bc+4ac