(2a+3b)cube how to solve using identity
amtulaleem2016:
by using( a+b)3 =a2+2ab+b2
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(2a)3 + (3b)3 + 3(2a.3b) (2a+3b)
8a3 + 27b3 + 18ab(2a+3b)
8a3 + 27b3+ 36a2b+54ab2
8a3 + 27b3 + 18ab(2a+3b)
8a3 + 27b3+ 36a2b+54ab2
Answered by
6
By using the
(a+b) ³ = a³ + b³ + 3a²b +3ab² the identity.
let a = 2a, b = 3b
(2a + 3b)³ = (2a)³ + (3b)³ + 3 (2a)²(3b)+3 (3b)²(2a)
= 8a³+27b³+9b (4a²) +6a (9b²)
= 8a³ + 27b³ + 36a² + 54b²
Hope it will help you
(a+b) ³ = a³ + b³ + 3a²b +3ab² the identity.
let a = 2a, b = 3b
(2a + 3b)³ = (2a)³ + (3b)³ + 3 (2a)²(3b)+3 (3b)²(2a)
= 8a³+27b³+9b (4a²) +6a (9b²)
= 8a³ + 27b³ + 36a² + 54b²
Hope it will help you
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