2A+3B------>A2B3 if 6moles of A reacts with 20 moles of B to form A2B3.Find the limiting reactant and Calculate the number of moles of A2B3 formed?
Answers
Answered by
2
Given:
6 moles of A and 20 moles of B have been taken in reaction container.
To find:
- Limiting reagent
- Moles of A2B3 formed.
Calculation:
We know that :
But in the reaction container, we have only 6 moles of A.
So, Limiting reagent is A.
Hence, reaction will be governed by the amount of "A".
So, 2 moles of A forms 1 mole of A2B3.
6 moles of A will form 3 moles of A2B3.
So, final answer is:
Answered by
1
Answer:
A is the limiting reagent and 3moles of A2B3 is formed
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