Physics, asked by AmmuShivani2262, 10 months ago

2A+3B------>A2B3 if 6moles of A reacts with 20 moles of B to form A2B3.Find the limiting reactant and Calculate the number of moles of A2B3 formed?

Answers

Answered by nirman95
2

Given:

 \rm{2A + 3B  \longrightarrow \: A_{2}B_{3}}

6 moles of A and 20 moles of B have been taken in reaction container.

To find:

  • Limiting reagent
  • Moles of A2B3 formed.

Calculation:

We know that :

 \sf{3 \: moles \: of \: B \: react \: with \: 2 \: moles \: of \: A}

 \sf{ \therefore \: 20 \: moles \: of \: B \: react \: with \:  \frac{2}{3} \times 20 \approx13.33 } \\ \sf{ \: moles \: of \: A}

But in the reaction container, we have only 6 moles of A.

So, Limiting reagent is A.

Hence, reaction will be governed by the amount of "A".

So, 2 moles of A forms 1 mole of A2B3.

\therefore 6 moles of A will form 3 moles of A2B3.

So, final answer is:

 \boxed{ \rm{3 \: moles \: of \: A_{2}B_{3} \: as \: product}}

Answered by naturelover4798
1

Answer:

A is the limiting reagent and 3moles of A2B3 is formed

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